写上过程、2/2x+3y+5/3x+2y=3/11 2/3(2x+3y)=7/6(3x+2y)+2.5

问题描述:

写上过程、2/2x+3y+5/3x+2y=3/11 2/3(2x+3y)=7/6(3x+2y)+2.5
解方程组、火速、2/2x+3y+5/3x+2y=3/11 2/3(2x+3y)=7/6(3x+2y)+2.5 火速解开,如果不嫌麻烦可以写上解释

因为2/3(2x+3y)=7/6(3x+2y)+2.5 ,等式两边同乘以6得;4/(2x+3y)=7/(3x+2y)+15 ;又因为:2/(2x+3y)+5/(3x+2y)=3/11 ,等式两边同乘以2得:4/(2x+3y)+10/(3x+2y)=6/11 ;两式作差得:17/(3x+2y)=-159/11;得3x+2y=-...