cos(75°+α)=1/3,且α为第三象限角,则sin(α-105°)=_.
问题描述:
cos(75°+α)=
,且α为第三象限角,则sin(α-105°)=______. 1 3
答
∵cos(75°+α)=
,且α为第三象限角,1 3
∴sin(75°+α)=-
=-
1−cos2(75°+α)
,2
2
3
则sin(α-105°)=sin[α-(180°-75°)]=-sin[180°-(75°+α)]=-sin(75°+α)=
.2
2
3
故答案为:
2
2
3