如图所示,在△ABC中,BD是∠ABC的平分线,DE⊥AB于E,若S△ABC=3.6cm2,AB=5cm,BC=4,则DE= _ cm.

问题描述:

如图所示,在△ABC中,BD是∠ABC的平分线,DE⊥AB于E,若S△ABC=3.6cm2,AB=5cm,BC=4,则DE= ___ cm.

∵BD是∠ABC的平分线,DE⊥AB,
∴点D到AB、BC的距离都等于DE,
∴S△ABC=S△ABD+S△BCD
=

1
2
AB•DE+
1
2
BC•DE,
=
1
2
×5•DE+
1
2
×4•DE,
=4.5DE,
∴4.5DE=3.6,
解得DE=
4
5
cm.
故答案为:
4
5