当k为何值时,方程x/(x-2)-2x/(x+2)=x+k/(x²-4)-1有增根.
问题描述:
当k为何值时,方程x/(x-2)-2x/(x+2)=x+k/(x²-4)-1有增根.
当k为何值时,方程x/(x-2)-2x/(x+2)=(x+k)/(x²-4)-1有增根
答
x/(x-2)-2x/(x+2)=(x+k)/(x²-4)-1方程两边同时乘以 (x-2)(x+2)(x+2)x - 2x(x-2)=x+k-(x-2)(x+2)∵ 方程有增根∴x=2 或 x= -2 ①当x=2时原式:8=2+kk= 6 ②当x= -2 时原式:-16= -2+kk= -14...