y=x[sin(Inx)-cos(Inx)]导数?
问题描述:
y=x[sin(Inx)-cos(Inx)]导数?
答
y'=1*[sin(Inx)-cos(Inx)]+x*[cos(lnx)*1/x+sin(lnx)*1/x]
=sin(Inx)-cos(Inx)+cos(lnx)+sin(lnx)
=2sin(Inx)