已知函数f(x)=根2sin2x号+根号2cos2x,x属于R,1,求f(3派/8}的值,2,求f(x)得最大值和最小正周期,
问题描述:
已知函数f(x)=根2sin2x号+根号2cos2x,x属于R,1,求f(3派/8}的值,2,求f(x)得最大值和最小正周期,
答
1、f(x)=√2sin2x+√2cos2x =2(cosπ/4sin2x+sinπ/4cos2x) =2sin(2x+π/4)所以:f(3π/8)=2sin(2X3π/8+π/4)=2sinπ=02、因:f(x)=2sin(2x+π/4)易知,最大值为2,最小正周期为:T=2π/2=π...