f[(3x+2)/2x-1]=x^2-1,求:f(1),f(x)
问题描述:
f[(3x+2)/2x-1]=x^2-1,求:f(1),f(x)
答
令(3x+2)/2x-1=1
则x=-3
f(1)=(-3)^2-1
=8
令(3x+2)/2x-1=y
则x=(-2-y)/(3-2y)
f(y)=[(-2-y)/(3-2y)]^2-1
f(x)=[(-2-x)/(3-2x)]^2-1