若根号x+y-3+绝对值xy+x+y-2=0,求x/y+y/x
问题描述：
若根号x+y-3+绝对值xy+x+y-2=0,求x/y+y/x
根号x+y-3+绝对值xy+x+y-2=0,求x/y+y/x
答
有题意得
x+y-3>=0
xy+x+y-2>=0
因为根号x+y-3+绝对值xy+x+y-2=0
则x+y-3=0
xy+x+y-2=0
xy=-1
x+y=3
x^2+y^2=11
x/y+y/x =(x^2+y^2)/xy=-11