1、因式分解：(x+1)(2x-1)-(2x-1)^2 2、计算：[x(x^2y^2-xy)-y(x^2+x^3y)]÷3x^2y
问题描述：
1、因式分解：(x+1)(2x-1)-(2x-1)^2 2、计算：[x(x^2y^2-xy)-y(x^2+x^3y)]÷3x^2y
答
④m平方x平方+n平方y平方-n平方x平方 ①x^2+3y-xy-3x =x(x-y)-3(x-y) =(x-y)(x-3) ②x^3+2x^2y-9x-18y =x (x+2y)-9(x
答
俊狼猎英团队为您
1、因式分(x+1)(2x-1)-(2x-1)^2
=(2X-1)［(X+1)-(2X-1)］
=-(2X-1)(X-2)
2、计算：[x(x^2y^2-xy)-y(x^2+x^3y)]÷3x^2y
=［X^2Y(XY-1)-X^2Y(1+XY)］÷3X^2Y
=X^2Y(XY-1-1-XY)÷3X^2Y
=-2/3
答
1、因式分(x+1)(2x-1)-(2x-1)^2
=(2X-1)［(X+1)-(2X-1)］
=-(2X-1)(X-2)
2、计算：[x(x^2y^2-xy)-y(x^2+x^3y)]÷3x^2y
=［X^2Y(XY-1)-X^2Y(1+XY)］÷3X^2Y
=X^2Y(XY-1-1-XY)÷3X^2Y
=-2/3