类比｛an｝为等差数列,则有bn=(a1+a2+a3+…+an)/n为等差数列,若｛cn｝为等比数列,则dn=?也为等比数列
问题描述：
类比｛an｝为等差数列,则有bn=(a1+a2+a3+…+an)/n为等差数列,若｛cn｝为等比数列,则dn=?也为等比数列
要的是具体过程.
答
Dn=(C1×C2×C3×……×Cn)^(1/n)成等比数列Bn=Sn/n=(nA1+(1/2)n(n-1)d)/n=A1+(n-1)(d/2)Bn是以A1为首项,d/2为公差的等差数列.类比Dn=(C1×C1×q^1×C1×q^2×……×C1×q^(n-1))^(1/n)=(C1^n×q^(n(n-1)/2))^(1/n)=...