(x+1)(x的平方+1)(x的 四次方+1)(x-1)等于几?
问题描述:
(x+1)(x的平方+1)(x的 四次方+1)(x-1)等于几?
答
(x+1)(x^2+1)(x^4+1)(x-1)=(x-1)(x+1)(x^2+1)(x^4+1)=(x^2-1)(x^2+1)(x^4+1)=(x^4-1)(x^4+1) =x^8-1
(x+1)(x的平方+1)(x的 四次方+1)(x-1)等于几?
(x+1)(x^2+1)(x^4+1)(x-1)=(x-1)(x+1)(x^2+1)(x^4+1)=(x^2-1)(x^2+1)(x^4+1)=(x^4-1)(x^4+1) =x^8-1