f(x)=lnx+2^x/x^2
问题描述:
f(x)=lnx+2^x/x^2
答
f'(x)=(lnx)'+((2^x)(x^(-2)))'=1/x+(2^x)'(x^(-2))+(2^x)(x^(-2))'=1/x+(2^x)ln2/(x^2)-(2^(x+1))/(x^3)
f(x)=lnx+2^x/x^2
f'(x)=(lnx)'+((2^x)(x^(-2)))'=1/x+(2^x)'(x^(-2))+(2^x)(x^(-2))'=1/x+(2^x)ln2/(x^2)-(2^(x+1))/(x^3)