sinx/2-cosx/2=1 答案为4kπ+π或4kπ+2π(k属于整数)
问题描述:
sinx/2-cosx/2=1
答案为4kπ+π或4kπ+2π(k属于整数)
答
sinx/2-cosx/2=1 ,√2*[sin(x/2)*√2/2-cos(x/2)*√2/2]=1,sin[(x/2)-π/4]=√2/2,即有,(X/2)-π/4=π/4,或(X/2)-π/4=3π/4,X=4Kπ+π或X=4Kπ+2π,(k属于整数Z).