函数y=√(5x-1)+√(7-2x)+1/(x-2)的自变量x取值范围是
问题描述:
函数y=√(5x-1)+√(7-2x)+1/(x-2)的自变量x取值范围是
答
根号下大于等于0
5x-1>=0
x>=1/5
7-2x>=0
x