设f(x)的定义域R上奇函数且满足f(x+2)=f(x).又当0≤x≤1时,f(x)=x 求(7.5)

问题描述:

设f(x)的定义域R上奇函数且满足f(x+2)=f(x).又当0≤x≤1时,f(x)=x 求(7.5)

f(7.5)
= f(5.5 + 2)
= f(5.5)
= f(3.5 + 2)
= f(3.5)
= f(1.5)
= f(-0.5)
= -f(0.5)
= -0.5