解关于x的分式方程:x+1/(x-2)=(a²+2a+1)/a.
问题描述:
解关于x的分式方程:x+1/(x-2)=(a²+2a+1)/a.
答
x+1/(x-2)=(a²+2a+1)/a(x²-2x+1)/(x-2)=(a²+2a+1)/aa(x²-2x+1)=(a²+2a+1)(x-2)ax²-(a²+4a+1)x+(2a²+5a+2)=0ax²-(a²+4a+1)x+(a+2)(2a+1)=0(x-a-2)(ax-2a-...