若实数x,y满足(x-y-5)的平方+/2x+3y+20/=0,求3x+2y+1的值
问题描述:
若实数x,y满足(x-y-5)的平方+/2x+3y+20/=0,求3x+2y+1的值
答
实数x,y满足(x-y-5)的平方+/2x+3y+20/=0
x-y-5=0 (1) ,2x+3y+20=0(2)
由(1)+(2)得3x+2y+15=0
3x+2y+1=-14