已知1/x+1/y=8,求2x-3xy+2y/x+2xy+y的值
问题描述:
已知1/x+1/y=8,求2x-3xy+2y/x+2xy+y的值
答
1/x+1/y=(x+y)/xy=8
x+y=8xy
2x-3xy+2y/x+2xy+y
=[2(x+y)-3xy]/[(x+y)+2xy]
=(16xy-3xy)/(8xy+2xy)
=13xy/10xy
=13/10