y=cos(2x²+1)求导
问题描述:
y=cos(2x²+1)求导
答
y=f(t) u=f(t)
y'=f'(t)*t' =-sin(2x²-1)*4x=-4xsin(2x²-1)
答
y=cos(2x²+1)
y'=-4xsin(2x²+1)