已知方程 x/2 - y/3 =1,取x = -2,x = 1/2,分别求出相应的y的值,并给出方程组的两组解
问题描述：
已知方程 x/2 - y/3 =1,取x = -2,x = 1/2,分别求出相应的y的值,并给出方程组的两组解
答
x/2 - y/3 =1,取x = -2,则-2/2 - y/3 =1,Y＝-6
x/2 - y/3 =1,取 x = 1/2,1/2/2 - y/3 =1 Y＝-9/4
方程组的两组解
x = -2,Y＝-6
x = 1/2 Y＝-9/4