已知x=1/2m+1,y=-1/3m+2,z=-1/6m-3,求x2+2xy+y2+2xz+2yz+z2的值.
问题描述：
已知x=1/2m+1,y=-1/3m+2,z=-1/6m-3,求x2+2xy+y2+2xz+2yz+z2的值.
答
x2+2xy+y2+2xz+2yz+z2
=(x+y+z)^2
=(1/2m+1-1/3m+2-1/6m-3)^2
=0