如图,在△ABC中,∠A:∠ABC:∠ACB=3:5:10,又△A′B′C≌△ABC,则∠BCA′:∠A′CA为_.
问题描述:
如图,在△ABC中,∠A:∠ABC:∠ACB=3:5:10,又△A′B′C≌△ABC,则∠BCA′:∠A′CA为______.
答
∵∠A:∠ABC:∠ACB=3:5:10,∴∠ACB=180°×103+5+10=100°,∵△A′B′C≌△ABC,∴∠A′CB′=∠ACB=100°,∴∠A′CA=180°-∠A′CB′=180°-100°=80°,∠BCA′=∠ACB-∠A′CB′=100°-80°=20°,∴∠BCA′...