Y=√x2-3+√5-x2/x+2求定义域.
问题描述:
Y=√x2-3+√5-x2/x+2求定义域.
答
Y=√x2-3+√5-x2/x+2
x^2-3>=0
5-x^2>=0
x+2≠0
解得-√5