已知abcd为数字,且1000a+100b+10c+d=100a+10b+102c+10d,求abcd
问题描述:
已知abcd为数字,且1000a+100b+10c+d=100a+10b+102c+10d,求abcd
答
ABCD = 1098
100a+10b+102c+10d = (100A+10B+C) + (100C+10D + C)
竖式就是
ABC
+CDC
--------
ABCD
显然A = 1
1BC
+ CDC
--------
1BCD
B = 0
10C
+ CDC
--------
10CD
C = 9
109
+ 9D9
--------
109D
D = 8
109
+ 989
--------
1098