分解因式:x∧2-y∧2-z∧2+2yz
问题描述：
分解因式:x∧2-y∧2-z∧2+2yz
答
x²-y²-z²+2yz
=x²-(y²-2yz+z²)
=x²-(y-z)²
=[x+(y-z)][x-(y-z)]
=(x+y-z)(x-y+z)