直线(2+m)x+(1-m)y+(4-3m)=0倾斜角范围
问题描述:
直线(2+m)x+(1-m)y+(4-3m)=0倾斜角范围
答
除了45°外
答
(2+m)x+(1-m)y+(4-3m)=0
k=(m-1)/(m+2)
=(m+2-3)/(m+2)
=1-3/(m+2)
所以
k≠1
此时倾斜角=45°
即
倾斜角范围是:【0,45°)U(45°,180°)