已知数列{An}中a1=1.且A(n+1)=6n*2^n-An.求通项公试An
问题描述：
已知数列{An}中a1=1.且A(n+1)=6n*2^n-An.求通项公试An
答
A(n+2)=6*(n+1)*2^(n+1)-A(n+1)
A(n+2)-A(n+1)=(6n+12)*2^n-A(n+1)+An
A(n+2)=(6n+12)*2^n+An
A3=37 A2=11 d=26
An={a1=1,
An=26n-15,n≥2}