sin4π/3cos5π/6tan(－4π/3)怎么做,求详细过程

sin cos的周期为2π tan周期为π
sin4π=sin(4π-4π)=sin0=0
3cos5π=3cos(5π-4π)=3cosπ=3*(-1)=-3
6tan(－4π/3)=6tan(－4π/3+π)=6tan(-π/3)=-6tan(π/3)=-6√3sin4π/3乘以cos5π/6乘以tan(－4π/3)=？sin（π/2＋α）＝cosαcos（π/2＋α）＝－sinαsin4π/3=sin(4π/3-2π)=sin(-2π/3)=-sin(2π/3)=-cos(2π/3-π/2)=-cos(π/6)=-√3/2cos5π/6=-cos(5π/6-π)=-cos(-π/6)=-cosπ/6=-√3/2tan(－4π/3)=tan(-4π/3+π)=tan(-π/3)=-tan(π/3)=-√3sin4π/3乘以cos5π/6乘以tan(－4π/3)=-√3/2*(-√3/2)*(-√3)=-3√3/4tanα ·cotα＝1sinα ·cscα＝1cosα ·secα＝1 sinα/cosα＝tanα＝secα/cscαcosα/sinα＝cotα＝cscα/secα sin2α＋cos2α＝11＋tan2α＝sec2α1＋cot2α＝csc2α 诱导公式 sin（－α）＝－sinα cos（－α）＝cosα tan（－α）＝－tanα cot（－α）＝－cotα sin（π/2－α）＝cosαcos（π/2－α）＝sinαtan（π/2－α）＝cotαcot（π/2－α）＝tanαsin（π/2＋α）＝cosαcos（π/2＋α）＝－sinαtan（π/2＋α）＝－cotαcot（π/2＋α）＝－tanα sin（π－α）＝sinαcos（π－α）＝－cosαtan（π－α）＝－tanαcot（π－α）＝－cotαsin（π＋α）＝－sinαcos（π＋α）＝－cosαtan（π＋α）＝tanαcot（π＋α）＝cotα背公式,多做题,不懂请追问,有帮助请采纳,谢谢.