ΔABC中,若sin²A+sin²B<sin²C,则ΔABC是什么Δ
问题描述:
ΔABC中,若sin²A+sin²B<sin²C,则ΔABC是什么Δ
答
sin²A+sin²B<sin²C两边同除以sin²C:sin²A/sin²C+sin²B/sin²C<1(sinA/sinC)²+(sinB/sinC)²<1根据正弦定理:sinA/sinC = a/c,sinB/sinC=b/c∴(a/c)²+...