化简(1)sin(α+π)cos(-α)sin(-α-π) (2)sin³(-α)cos(2π+α)tan(-α-π)
问题描述:
化简(1)sin(α+π)cos(-α)sin(-α-π) (2)sin³(-α)cos(2π+α)tan(-α-π)
(1)sin(α+π)cos(-α)sin(-α-π)
(2)sin³(-α)cos(2π+α)tan(-α-π)
答
(1)sin(α+π)cos(-α)sin(-α-π) =(-sinα)*cosα*(sinα)=-sin²α*cosα(2)sin³(-α)cos(2π+α)tan(-α-π)=(-sinα)³*cosα*(-tanα)=-sin³α*cosα*(-sinα/cosα)=(sinα)^4...