椭圆x^2/a^2+y^2/b^2=1与椭圆x^2/25+y^2/16=1有相同的长轴,椭圆x^2/a^2+y^2/b=1的短轴长与椭圆y^2/21+x^2/9=1的短轴长相等,则a^2=?b^2=?

问题描述:

椭圆x^2/a^2+y^2/b^2=1与椭圆x^2/25+y^2/16=1有相同的长轴,椭圆x^2/a^2+y^2/b=1的短轴长与椭圆y^2/21+x^2/9=1的短轴长相等,则a^2=?b^2=?

由题意得:a=5,b=3
所以,a^2=2,b^2=9