cos^2(x)-√3/2*sin2x的值域
问题描述:
cos^2(x)-√3/2*sin2x的值域
答
原式=(1+cos2x)/2-√3/2sin2x
=1/2cos2x-√3/2sin2x+1/2
=cos2xcosπ/3-sin2xsinπ/3+1/2
=cos(2x+π/3)+1/2
-1