已知n为正整数,且1/(1+n)+1/(3+n)+1/(6+n)>19/36,求N的最小值
问题描述:
已知n为正整数,且1/(1+n)+1/(3+n)+1/(6+n)>19/36,求N的最小值
答
19/36=1/(1+3 )+1/(3+3)+1/(6+3)
1/(1+n )+1/(3+n)+1/(6+n)>1/(1+3 )+1/(3+3)+1/(6+3)
n