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化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α)

分类: 作业答案 • 2022-07-03 13:29:08
问题描述：

化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α)

答

原式
=sin(-α)(-cosα)(-sinα)/(-cosα)sinαsinαcosα
=-sinαcosαsinα/(-cosαsinαsinαcosα)
=1/cosα

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