将复数z=-2(sinπ/3-icosπ/3)化为三角形式,
问题描述:
将复数z=-2(sinπ/3-icosπ/3)化为三角形式,
答
z=-2(sinπ/3-icosπ/3)
=2(-sinπ/3+icosπ/3)
=2(-cos(π/6)+isin(π/6))
=2(cos(π-π/6)+isin(π-π/6))
=2(cos(5π/6)+isin(5π/6))