已知y=y1+y2 y1与x+1成正比例 y2与x成正比例且当x=1时y=0 x=4时y=9 求档x=2时y的值

问题描述:

已知y=y1+y2 y1与x+1成正比例 y2与x成正比例且当x=1时y=0 x=4时y=9 求档x=2时y的值

设:y1 = k1(x1+1);
y2 = k2*x2;
由x = 1,y = 0; x = 4 ,y = 9;可以得到下面二个式子:
0 = k1(1+1)+k2*1;
9 = k1(4+1)+k2*4;
可以推出k1= -3,k2 = 6
所以当x = 2时,y = 3k1+2k2 = 3;