等差数列an,a1+a4+a7=9,a10=9,求S10
问题描述:
等差数列an,a1+a4+a7=9,a10=9,求S10
答
a1+a4+a7
=a1+a1+3d+a1+6d
=3a1+9d
=9
a10=a1+9d=9
得
a1=0
d=1
S10=(a1+a10)*10/2
=9*10/2
=45