(x^2-8x)(3-9^2)=(8-x)^2

问题描述:

(x^2-8x)(3-9^2)=(8-x)^2

(x^2-8x)(3-9^2)=(8-x)^2
(x²-8x)(3-9²)=(8-x)²
78x(8-x)=(8-x)²
(8-x)²-78x(8-x)=0
(8-x)(8-x-78x)=0
(8-x)(8-79x)=0

x①=8
x②=8/79