-4/(y^4+1)-2/(y^2+1)-1/(y+1)+1/(y-1)=2y/(-1+y^8)
问题描述:
-4/(y^4+1)-2/(y^2+1)-1/(y+1)+1/(y-1)=2y/(-1+y^8)
解方程
答
原方程左边=-4/(y^4+1) -2/(y^2+1) +[1/(y-1) -1/(y+1)]=-4/(y^4+1) -2/(y^2+1) +[(y+1)-(y-1)]/[(y-1)*(y+1)]=-4/(y^4+1) -2/(y^2+1) +2/(y^2-1)=-4/(y^4+1) +2[1/(y^2-1) -1/(y^2+1)]=-4/(y^4+1) +2[(y^2+1)-(y^2-...