设集合A=[x kπ+π/4≤x≤kπ+π/2,π∈Z},集合B={x 6+x-x2≥0},求A∩B,
问题描述：
设集合A=[x kπ+π/4≤x≤kπ+π/2,π∈Z},集合B={x 6+x-x2≥0},求A∩B,
答
A∩B = [-2,-π/2] ∪ [π/4,π/2].根据题目可知,集合B={ x | -2≤x≤3} = [-2,3]当k=-1时：集合A= [ -0.75π,-0.5π] .注意到 -0.75π -2 ,∴[ -0.75π,-0.5π]部分包含于[-2,3]中当k=0时：集合A= [...