x²+5xy+6y²+x+3y
问题描述:
x²+5xy+6y²+x+3y
答
原式=(x+2y)(x+3y)+(x+3y)
=(x+3u)(x+2y+1)
x²+5xy+6y²+x+3y
原式=(x+2y)(x+3y)+(x+3y)
=(x+3u)(x+2y+1)