若向量ab满足a+b=(-2,-1),a-b=(4,-3),则a×b=

问题描述:

若向量ab满足a+b=(-2,-1),a-b=(4,-3),则a×b=

已知a+b=(-2,-1)①,a-b=(4,-3)②
将两式相加得2a=(2.-4) ①-②得2b=(-6,2)
则a=(1,-2) b=(-3,1)
a*b=1*(-3)+(-2)*1=-5

由a+b=(-2,-1),a-b=(4,-3)得a=(1.-2)b=(-3.1)
a×b=1 -3
-2 1
=-5

(a+b)^2=a^2+b^2+2ab=5
(a-b)^2=a^2+b^2-2ab=25
(a+b)^2-(a-b)^2=4ab=-20
所以
ab=-5