初二整式方程一道-____________________-(1+根号2）x²-（3+根号2）x+2=0
问题描述：
初二整式方程一道-____________________-
(1+根号2）x²-（3+根号2）x+2=0
答
(1+√2)x²-[(1+√2)+2]x+2=0
(1+√2)x²-(1+√2)x-2x+2=0
(1+√2)x(x-1)-2(x-1)=0
(x-1)[(1+√2)x-2]=0
x=1,x=2/(1+√2)
即x=1，x=2√2-2
答
(1+√2)x^2-(3+√2)x+2=0
(x-1)[(1+√2)x-2]=0
x=1或x=2/(1+√2)=2√2-2