用因式分解法求 (2x-1)^2-(2x-1)-2=0
问题描述:
用因式分解法求 (2x-1)^2-(2x-1)-2=0
答
(2x-1)^2-(2x-1)-2=0
(2x-1-2)(2x-1+1)=0
2x(2x-3)=0
x1=0 x2=3/2
答
(2x-1)^2-(2x-1)-2=0
{(2x-1)+1} {(2x-1)-2}=0
2x(2x-3)=0
x1=0,x2=3/2