x+y=32,x²-y²=48
问题描述：
x+y=32,x²-y²=48
求xy
答
x+y=32,x²-y²=48
x-y = (x²-y²)÷ (x+y) = 48 ÷ 32 = 3/2
x= (32+3/2)÷2
= 16 又 4分之3
= 67 /4
y= 32 - 16 又 4分之3
= 15 又 4分之1
= 61/4
xy= 61x67 /16
= 16 分之 4087