m²-4m+10=0怎么解?(要有过程)
问题描述:
m²-4m+10=0怎么解?(要有过程)
(6-x)(8-x)=24又怎么解?(也要有过程)
答
m²-4m+10=0m²-4m+4+6=0(m-2)²+6=0实数范围内无解复数:令i² = -1(m-2)² = 6i²m =2 ±i√(6)(6-x)(8-x)=24x² - 14x + 48 = 24x² - 14x + 24 = 0用求根工式:x = [14±√...