a,b均为质数,且3a+4b=41,则a+b是多少?
问题描述：
a,b均为质数,且3a+4b=41,则a+b是多少?
答
a = 7 ,b = 5 ,a + b = 12
a = 11 ,b = 2 ,a + b = 13还可以，不过不完整a = (41 - 4b)/3 = 14 - b - (1 + b)/3b = (41 - 3a) /4