x²-x-12/x²-x=4

问题描述:

x²-x-12/x²-x=4
用换元法
分数线上面只有12

x²-x-12/(x²-x)=4设x²-x=tt-12/t=4∴t²-12=4tt²-4t-12=0(t-6)(t+2)=0∴t=6或-2当x²-x=6时x²-x-6=0(x-3)(x+2)=0x=3或x=-2当x²-x=-2时x²-x+2=0Δ=1-4