已知,1/a+1/b=1/6,1/b+1/c=1/9,1/a+1/c=1/15,则abc/ab+bc+ac=_.

问题描述:

已知,

1
a
+
1
b
1
6
1
b
+
1
c
1
9
1
a
+
1
c
1
15
,则
abc
ab+bc+ac
=______.

由已知得,

1
a
+
1
b
1
6
ac+bc
abc
=
1
6

1
b
+
1
c
1
9
ab+ac
abc
=
1
9

1
a
+
1
c
1
15
ab+bc
abc
=
1
15

2(ab+bc+ac)
abc
=
31
90

abc
ab+bc+ac
=
45
31

故答案为:
45
31