函数f(x)=x²-3x+2.则f(x+1)=
问题描述:
函数f(x)=x²-3x+2.则f(x+1)=
答
f(x+1)=
(X+1)^2-3(x+1)+2
=x^2-x
函数f(x)=x²-3x+2.则f(x+1)=
f(x+1)=
(X+1)^2-3(x+1)+2
=x^2-x